Curso de Programación en C/Prog20

• Prog20
  • Resultado
  • Explicación

Prog20

/* Prog20.c -- Conversiones interesantes con floats */

#include <stdio.h>

int main( void )
{
  float  n1 = 3.0;
  double n2 = 3.0;
  long   n3 = 2000000000,
         n4 = 1234567890;

  printf( "Con conversiones naturales: %f %lf    %ld %ld\n", n1, n2, n3, n4 );
  printf( "Con %%.1e:                   %.1e  %.1e     %.1e    %.1e\n",
                                                             n1, n2, n3, n4 );
  printf( "Con %%ld:                    %ld        %ld  %ld          %ld\n",
                                                             n1, n2, n3, n4 );

  return 0;
}

Resultado

[rrc@Pridd CClase]$ gcc -Wall -O2 -o Prog20 Prog20.c
Prog20.c: In function ‘main’:
Prog20.c:14: warning: format ‘%.1e’ expects type ‘double’, but argument 4 has type ‘long int’
Prog20.c:14: warning: format ‘%.1e’ expects type ‘double’, but argument 5 has type ‘long int’
Prog20.c:16: warning: format ‘%ld’ expects type ‘long int’, but argument 2 has type ‘double’
Prog20.c:16: warning: format ‘%ld’ expects type ‘long int’, but argument 3 has type ‘double’
[rrc@Pridd CClase]$ ./Prog20
Con conversiones naturales: 3.000000 3.000000    2000000000 1234567890
Con %.1e:                   3.0e+00  3.0e+00     3.1e+46    6.6e-316
Con %ld:                    0        1074266112  0          1074266112
[rrc@Pridd CClase]$